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Arithmetic AptitudeA.

456

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987

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345

Aptitude

Arithmetic Aptitude

Permutation and Combination

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simple calculation via expanding

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(30*29*28!)/28!after cancelling 28! from both numerator and denomenator,we get,30*29 which is equal to 870.

Tushar GoyalScore : *3*

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A.

Rs. 9600

B.

Rs. 8500

C.

Rs. 8450

D.

Rs. 8400

Aptitude

Arithmetic Aptitude

Partnership

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Ratio of their shares = 22500 : 35000 = 9 : 14

Deepak's share = Rs. (13800 * 14/23) = Rs. 8400

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Ratio of their shares = 22500 : 35000=9 : 14Deepak's share = Rs.(13800�14/23)= Rs. 8400

Aman SadhwaniScore : *20*

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22500/35000=9/14 deepak share=(14/23)13800=8400

Hemant PoddarScore : *40*

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22500/35000=9/14deepak_share*(1+9/14)=13800deepak_share*(23/14)=13800deepak_share=(14/23)*13800=8400

Rohit KumarScore : *17*

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ratio of thier shares =22500/35000=9/14 therefore total share =9+14=23Deepak share =total profit *(deepak share/total share)=13800*(14/23)= 8400

Krishna GundapaneniScore : *0*

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A.

3 : 7 : 5

B.

6 : 10 : 5

C.

6 : 10 : 7

D.

6 : 7 : 5

Aptitude

Arithmetic Aptitude

Partnership

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Let initial investment of A is 3x and B is 5x.

Then C's investment is also 5x

But most important to note in this question is the time duration of investment.

Like, A invested for 12 months, B invested for 12 months and C invested for 6 months.

Then, A : B : C = (3x * 12) : (5x * 12) : (5x * 6)

= 36 : 60 : 30

= 6 : 10 : 5

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Rs 200

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Rs 300

C.

Rs 500

D.

Rs 400

Aptitude

Arithmetic Aptitude

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Let C = x.

Then, B = x/2 and A = x/4

A : B : C = 1 : 2 : 4.

C's share Rs. [(4/7) * 700) = 400

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option verify

Rakesh SingamaneniScore : *117*

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A.

3

B.

4

C.

5

D.

6

Aptitude

Arithmetic Aptitude

Partnership

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Suppose B joined after x months.

Then, 21000 * 12 = 36000 * (12 - x)

=> 36x = 180

=> x = 5

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A invested Rs. 21,000 & B invested Rs. 36000. Their investment is in the ratio 7:12.That implies 21000*12 = 36000*7 (Simple Maths)This means that profit would be same if 21000 is invested for 12 months or 36000 is invested for 7 months. So, B invested for 7 months.After how many months B joined? It's 12-7=5. B started investing after 5 months.

Adarsh SinghalScore : *21*

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A.

Rs. 2000

B.

Rs. 3000

C.

Rs. 4000

D.

Rs. 5000

Aptitude

Arithmetic Aptitude

Partnership

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Suppose Ramesh invested Rs. x.

Then, Manoj : Ramesh = 20000 * 6 : x * 12.

=> 120000/12x : 6000/3000

=> x = 120000/24 = 5000

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hey manoj value is 120000 not 20000. so ans would be 30000. its B.

Kumar ShubhenduScore : *457*

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Suppose Ramesh invested Rs. x.Then, Manoj : Ramesh = 120000 * 6 : x * 12.=> 720000/12x : 3000/6000=> x = 60000*2 = 120000ans will be 120000

Anand Kumar MehtaScore : *61*

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The question is itself wrong. The answer's according to Rs. 20,000 whereas the question has Rs. 1,20,000 given!

Tilak ParmarScore : *16*

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ramesh invested 120000 not 20000.so ans will be 30000

Sheelu ChaturvediScore : *178*

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The options to the givne question are wrong.The given answer 5000 is correct if manoj had invested 20000 but in the question it is clearly mentioned that manoj's investment is 120000 so according to the given data in the question the answer is 30000 which is not available in the options

Suraj YalamanchiScore : *564*

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A.

Rs. 7000

B.

Rs. 6000

C.

Rs. 4000

D.

Rs. 5000

Aptitude

Arithmetic Aptitude

Partnership

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Just take care of the months of investment, rest all will be simple.

Yogesh : Pranab : Atul = 45000 * 12 : 60000 * 9 : 90000 * 3

= 2 : 2 : 1

Atul's share = Rs. 20000 * (1/5) = Rs. 4000

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Name Investment ContributionYogesh 45000 for 12 months 45000*12 = 540000Pranab 60000 for 9 months 60000*9 = 540000Atul 90000 for 3 months 90000*3 = 270000Clearly, contribution ratio is 2:2:1. Their contribution is 40%, 40%, 20% respectively.Atul's profit is 20% of total profit which is Rs. 20000 i.e. Rs. 4000

Adarsh SinghalScore : *21*

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A.

Rs 48000

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Rs 47000

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Rs 47400

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Rs 48400

Aptitude

Arithmetic Aptitude

Partnership

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A : B = 3 : 2 = 6 : 4

=> A : C = 2 : 1 = 6 : 3

=> A : B : C = 6 : 4 : 3

B's share = (4/13) * 157300 = 48400

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A.

17:5

B.

17:6

C.

17:4

D.

17:3

Aptitude

Arithmetic Aptitude

Partnership

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In this type of question as time frame for both investors is equal then just get the ratio of their investments.

P : Q = 85000 : 15000

= 85 : 15

= 17 : 3

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compare the product ( money* time it was invested for). So, here, (85*2) : (15*2) is the ratio.

Parasar JatakScore : *235*

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A.

14700

B.

15000

C.

13500

D.

12000

Aptitude

Arithmetic Aptitude

Partnership

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Let C = x.

Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.

So, x + x + 5000 + x + 9000 = 50000

=> 3x = 36000

=> x = 12000.

A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.

A's share = Rs. (35000 * 21/50 ) = Rs. 14,700.

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A.

19:49:64

B.

20:49:64

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20:49:65

D.

20:50:64

Aptitude

Arithmetic Aptitude

Partnership

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Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively.

Then, 14x : 8y : 7z = 5 : 7 : 8

Now, 14x/8x = 5/7

=> y = (49/20)x

Also, 14x/7z = 5/8

=> z = (16/5)x

=> x : y : z = x : (49/20)x : (16/5)x

= 20 : 49 : 64

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A.

17 : 1

B.

17 : 2

C.

17 : 3

D.

17 : 4

Aptitude

Arithmetic Aptitude

Partnership

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P : Q = 85000 : 15000 = 17:3

Note: If both have invested for different period of times then we had to multiply with number of months to get the desired ratio.

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Rs 690

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Rs 990

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Rs 790

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Rs 890

Aptitude

Arithmetic Aptitude

Partnership

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A : B : C = (8000 * 6) : (4000 * 8) : (8000 * 8)

= 48 : 32 : 64

= 3 : 2 : 4

So, B share = (2/9) * 4005 = Rs 890

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Rs 2500

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Rs 2400

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Rs 2300

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None of above

Aptitude

Arithmetic Aptitude

Partnership

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Nirmal : Kapil = 9000*12 : (12000 * 6 + 6000 * 6) = 1 : 1

Kapils share = Rs. [4600 * (1/2)) = Rs. 2300

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A.

2 : 3 : 5

B.

3 : 4 : 7

C.

5 : 6 : 4

D.

1 : 3 : 5

Aptitude

Arithmetic Aptitude

Partnership

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A : B : C = (40000 x 36) : (80000 x 12 + 40000 x 24) : (120000 x 24 + 40000 x 12)

= 144 : 192 : 336

= 3 : 4 : 7.

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A.

12628

B.

18245

C.

10253

D.

11235

Aptitude

Arithmetic Aptitude

Partnership

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Ratio of their shares = (35000 * 8) : (42000 * 10) = 2 : 3.

Reena's share = Rs. 31570 * (2 / 5) = Rs. 12628.

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(2/5)???? from where that term been taken

Rajat JadonScore : *297*

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A.

130

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145

C.

140

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144

Aptitude

Arithmetic Aptitude

Partnership

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Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3.

Let their initial investments be 6x, 2x and 3x respectively.

A : B : C = (6x * 2 + 3x * 10) : (4x * 12) : (3x * 12) = 42 : 48 : 36 = 7 : 8 : 6.

B's share = Rs. (378 * 8/21) = Rs. 144.

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17 : 23

B.

17 : 3

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12 : 25

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17 : 40

Aptitude

Arithmetic Aptitude

Partnership

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P : Q = 85000 : 15000 = 86 : 15 = 17 : 3.

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A.

20000

B.

30000

C.

40000

D.

60000

Aptitude

Arithmetic Aptitude

Partnership

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Suppose Y invested Rs. y.

Then 40000/y = 2/3 or y = 60000 .

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A.

120

B.

130

C.

150

D.

160

Aptitude

Arithmetic Aptitude

Partnership

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A : B : C = 7 : 8 : 11.

Hire charges paid by B = Rs. (520 * 8/26) = Rs. 160.

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A.

300

B.

350

C.

400

D.

450

Aptitude

Arithmetic Aptitude

Partnership

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Let C = x.

Then B = x/2 and A = x/4

A:B:C = 1:2:4.

C's share Rs.[(4/7)*700) = 400

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A.

Rs. 45

B.

Rs. 50

C.

Rs. 60

D.

Rs. 40

Aptitude

Arithmetic Aptitude

Partnership

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A : B : C = (10 × 7) : (12 × 5) : (15 × 3)

= 70 : 60 : 45

= 14 : 12 : 9

C's rent = Rs.(175 × 9/35)

=Rs. 45

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10

B.

12

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14

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16

Aptitude

Arithmetic Aptitude

Profit and Loss

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3 pairs of gloves = 2x54 = 108 ; 1 pairs of gloves = 363 pairs of leg pads = 2 x 36 = 1 pairs of leg pads = 243 cricket balls = 2 x 24 = 48cost of 1 cricket ball = 16.

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3 pairs of gloves = 2x54 = 108 ; 1 pairs of gloves = 36; 3 pairs of leg pads = 2(GLOBES) x 36 =72; SO , 1 pairs of leg pads = 24 ; 3 cricket balls = 2(L.P.) x 24 = 48 ; cost of 1 cricket ball = (24*2)/3= 16 .

Amit YadavScore : *9*

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0

1 ball price = (2/3)*(2/3)*(2*54/3)=161 ball = 2/3 pad like as 1 pad = 2/3 gloves like as 1 gloves = 2*54/3;so above is calculation

Dheeraj KumarScore : *22*

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A.

1/63

B.

1/9

C.

2/15

D.

2/63

Aptitude

Arithmetic Aptitude

Probability

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Let A be the event that X is selected and B is the event that Y is selected.P(A) = 1/7, P(B) = 2/9.Let C be the event that both are selected.P(C) = P(A) × P(B) as A and B are independent events:= (1/7)× (2/9) = 2/63

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Take lcm of 7&9

Y YashothaaScore : *130*

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A.

1/3

B.

8/11

C.

2/11

D.

4/15

Aptitude

Arithmetic Aptitude

Probability

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Total number of balls = (8 + 7 + 6) = 21.Let E= event that the ball drawn is neither red nor green= event that the ball drawn is blue.n(E) = 7.P(E) =n(E)/n(S)=7/21=1/3.

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1/9

B.

1/12

C.

1/2

D.

3/4

Aptitude

Arithmetic Aptitude

Probability

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Total numbers in a die=6P(mutliple of 3) = 2/6 = 1/3P(multiple of 4) = 1/6P(multiple of 3 or 4) = 1/3 + 1/6 = 1/2

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A.

20/34

B.

12/34

C.

25/34

D.

29/34

Aptitude

Arithmetic Aptitude

Probability

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The events of selection of two person is redefined as first is a girl and second is a boy or first is boy and second is a girl or first is a girl and second is a girl.So the required probability:=(8/17×9/16)+(9/17×8/16)+(8/17×7/16)=9/34+9/34+7/34= 25/34

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WRONG answer.right answer = 27/34p stands for probability.p(both selected are GIRL) = (9/17) X(8/16) = 9/34p( 1 boy and 1 girl) = 2 X(8 x 9)/(17 x16) = 18/34sum= 27/34

Sonu DixitScore : *22*

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Answer is 27/34 because in given solution your consdiering 8/17*7/16 which is the probabiltiy of both boys selected and your are asking atleast one girl .. correct solution (1 girl + 1 boy) or (1 boy + 1 girl )or both girls ..your explaination is right but calculation is wrong...(8/17×9/16)+(9/17×8/16)+(9/17×8/16) is correct...

Rahul VermaScore : *167*

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the required probability is(9/17*8/16)+(8/17*9/16)+(9/17*8/16)=9/34+9/34+9/34=27/34

Pankaj SonkariaScore : *2459*

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A.

3/7

B.

1/2

C.

3/11

D.

4/7

Aptitude

Arithmetic Aptitude

Probability

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Let number of balls = (6 + 8) = 14.Number of white balls = 8.P (drawing a white ball) = 8 /14=4/7.

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A.

1/3

B.

1/2

C.

1/6

D.

1/8

Aptitude

Arithmetic Aptitude

Probability

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P(first letter is not vowel)=2/4P(second letter is not vowel)=1/3So,probability that none of letters would be vowels is =(2/4)x(1/3)=1/6

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mmm

Venu AileniScore : *312*

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+10 ...

Diwakar NScore : *430*

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A.

1/216

B.

2/216

C.

4/216

D.

1/36

Aptitude

Arithmetic Aptitude

Probability

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The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:=6×6×6×6=64n(S)=64Let X be the event that all dice show the same face.X ={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}n(X)=6Hence required probability =n(X)n(S)=664= 1/216

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6^4 is 1296, therefore 6/1296=1/216

Komal SaiScore : *364*

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